∆ ABC is isosceles with AB = AC = 7.5 cm, and BC = 9 cm (in Figure). The height AD from A to BC, is 6 cm. Find the area of ∆ ABC. What will be the height from C to AB i.e., CE?
triangle ABC is isosceles with AB AC 7.5 cm
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
ABC is an isosceles triangle with AB = AC and BC = 16 cm and
Let triangle ABC be an isosceles with AB=AC. Suppose that the angle
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
Delta ABC is isosceles with AB = AC = 7.5 m and BC = 9 cm The height A
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area
triangle ABC is isosceles with AB equals to AC equal to 7.5 cm and
Triangle ABC is isosceles with AB=AC=7.5cm and bc=9 cm. the height
AABC is iso Fig 11.26 Cis isosceles with AB=AC = 7.5 cm and BC =9
6. In the adjoining figure, ABC is an isosceles triangle with AB
triangle ABC is an isosceles triangle with AB = AC=13 cm. AD is the me
NCERT Solutions for Class 7 Maths Chapter 11 Perimeter and Area Ex